Search This Blog

Friday, 22 June 2018

Mean and Standard Deviation, Sample Mean

Numerical Problem

Q. Mean of Sample is 100 and Standard deviation is 5. What will be mean and standard deviation for sample Size 25?

Solution:  Mean of Sample μ(x)= μ= 100
                 Standard deviation is  σ(x)= σ/ √ n 
                                                            =5/√ 25 
                                                            =1

No comments:

Post a Comment