Numerical Problem
Q. Mean of Sample is 100 and Standard deviation is 5. What will be mean and standard deviation for sample Size 25?
Solution: Mean of Sample μ(x)= μ= 100
Standard deviation is σ(x)= σ/ √ n
=5/√ 25
=1
Q. Mean of Sample is 100 and Standard deviation is 5. What will be mean and standard deviation for sample Size 25?
Solution: Mean of Sample μ(x)= μ= 100
Standard deviation is σ(x)= σ/ √ n
=5/√ 25
=1
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